Medium
In most cases,for a rise of $10 \ K$ temperature,the rate constant is doubled or tripled. This is due to the reason that
- Acollision frequency increases by a factor of $2$ to $3$
- Bfraction of molecules possessing threshold energy increases by a factor of $2$ to $3$
- CActivation energy is lowered by a factor of $2$ to $3$
- Dnone of these
Explore More
Similar Questions
When the temperature of a reaction is raised by $10^{\circ}C$,how many times the rate will be enhanced?
According to Arrhenius theory,the activation energy is
Easy
View SolutionThe relation between the fraction of molecules $\left( \frac{N_E}{N_T} \right)$ and temperature is explained by the Boltzmann and Maxwell distribution graph.
Difficult
View SolutionFor an exothermic reaction $X \rightarrow Y$,the activation energy is $30 \ kJ \ mol^{-1}$. If the enthalpy change $(\Delta H)$ for the reaction is $-20 \ kJ \ mol^{-1}$,then the activation energy for the reverse reaction is . . . . . . $kJ \ mol^{-1}$.
Medium
View SolutionFor the reaction $A_2 + B_2 \rightleftharpoons 2 AB$,the activation energies $(E_a)$ for the forward and backward reactions are $180 \ kJ \ mol^{-1}$ and $200 \ kJ \ mol^{-1}$ respectively. If a catalyst lowers the $E_a$ for both reactions by $100 \ kJ \ mol^{-1}$,which of the following statements is correct?
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo