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(B) The combustion reaction of benzene is: $C_6H_6(l) + \frac{15}{2} O_2(g) \longrightarrow 6 CO_2(g) + 3 H_2O(l)$Given: $\Delta H_f[CO_2(g)] = -393.5

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$48$

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(B) The combustion reaction of benzene is: $C_6H_6(l) + \frac{15}{2} O_2(g) \longrightarrow 6 CO_2(g) + 3 H_2O(l)$Given: $\Delta H_f[CO_2(g)] = -393.5 \ kJ \ mol^{-1}$,$\Delta H_f[H_2O(l)] = -286.0 \ kJ \ mol^{-1}$,and $\Delta H_c[C_6H_6] = -3267.0 \ kJ \ mol^{-1}$Using the formula: $\Delta H_c = \Sigma \Delta H_f(	ext{products}) - \Sigma \Delta H_f(	ext{reactants})$$-3267.0 = [6 	imes (-393.5) + 3 	imes (-286.0)] - [\Delta H_f(C_6H_6) + 0]$$-3267.0 = [-2361.0 - 858.0] - \Delta H_f(C_6H_6)$$-3267.0 = -3219.0 - \Delta H_f(C_6H_6)$$\Delta H_f(C_6H_6) = -3219.0 + 3267.0 = 48 \ kJ \ mol^{-1}$

Allotrope	$\Delta_f H^{\Theta}$
$i$. Graphite	$b$. $0 \ kJ/mol$
$ii$. Diamond	$c$. $1.90 \ kJ/mol$
$iii$. Fullerene	$a$. $38.1 \ kJ/mol$

Consider the following data :
Heat of formation of $CO_{2(g)} = -393.5 \ kJ \ mol^{-1}$
Heat of formation of $H_2O_{(l)} = -286.0 \ kJ \ mol^{-1}$
Heat of combustion of benzene $= -3267.0 \ kJ \ mol^{-1}$
The heat of formation of benzene is $........... \ kJ \ mol^{-1}$. $(Nearest \ integer)$

Similar Questions

Match the following allotropes of carbon with their standard enthalpy of formation $(\Delta_f H^{\Theta})$:
Allotrope $\Delta_f H^{\Theta}$
$i$. Graphite $b$. $0 \ kJ/mol$
$ii$. Diamond $c$. $1.90 \ kJ/mol$
$iii$. Fullerene $a$. $38.1 \ kJ/mol$

At constant pressure,the heat of formation of a compound is not dependent on temperature,when

If $\Delta H_f (H_2O) = X$,then the heat of neutralization of $CH_3COOH$ and $NaOH$ will be:

Identify $I, II, III$ in the given Born-Haber cycle diagram for the dissolution of an ionic solid $AB(s)$:
$AB(s) \xrightarrow{I} A^+(aq) + B^-(aq)$
$AB(s) \xrightarrow{II} A^+(g) + B^-(g)$
$A^+(g) + B^-(g) \xrightarrow{III} A^+(aq) + B^-(aq)$

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Consider the following data :Heat of formation of $CO_{2(g)} = -393.5 \ kJ \ mol^{-1}$Heat of formation of $H_2O_{(l)} = -286.0 \ kJ \ mol^{-1}$Heat of combustion of benzene $= -3267.0 \ kJ \ mol^{-1}$The heat of formation of benzene is $........... \ kJ \ mol^{-1}$. $(Nearest \ integer)$