Consider the data: Class 65-85 85-10 | vedclass

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(C) To find the median class and modal class,we first calculate the cumulative frequency $(cf)$:						Class			Frequency $(f)$			Cumulative Frequency $

Vedclass · Accepted Answer

$20$

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(C) To find the median class and modal class,we first calculate the cumulative frequency $(cf)$:						Class			Frequency $(f)$			Cumulative Frequency $(cf)$							$65-85$			$4$			$4$							$85-105$			$5$			$9$							$105-125$			$13$			$22$							$125-145$			$20$			$42$							$145-165$			$14$			$56$							$165-185$			$7$			$63$							$185-205$			$4$			$67$			Total frequency $N = 67$. Thus,$\frac{N}{2} = \frac{67}{2} = 33.5$.The cumulative frequency just greater than $33.5$ is $42$,which corresponds to the class interval $125-145$. Therefore,the median class is $125-145$. The upper limit of the median class is $145$.The highest frequency is $20$,which corresponds to the class interval $125-145$. Therefore,the modal class is $125-145$. The lower limit of the modal class is $125$.Required difference = (Upper limit of median class) - (Lower limit of modal class) = $145 - 125 = 20$.

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$
Frequency	$5$	$12$	$18$	$40$	$15$	$7$	$3$

Consider the data:

Class $65-85$ $85-105$ $105-125$ $125-145$ $145-165$ $165-185$ $185-205$

Frequency $4$ $5$ $13$ $20$ $14$ $7$ $4$

The difference between the upper limit of the median class and the lower limit of the modal class is:

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Class	$65-85$	$85-105$	$105-125$	$125-145$	$145-165$	$165-185$	$185-205$
Frequency	$4$	$5$	$13$	$20$	$14$	$7$	$4$

Consider the data: Class $65-85$ $85-105$ $105-125$ $125-145$ $145-165$ $165-185$ $185-205$ Frequency $4$ $5$ $13$ $20$ $14$ $7$ $4$ The difference between the upper limit of the median class and the lower limit of the modal class is: