In the formula $\bar{x} = a + h \left( \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} \right)$,for finding the mean of grouped frequency distribution,$u_{i}$ is equal to
- A$\frac{x_{i} + a}{h}$
- B$\frac{x_{i} - a}{h}$
- C$h(x_{i} - a)$
- D$\frac{a - x_{i}}{h}$
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Similar Questions
The median of the following frequency distribution is $28.5$ and the total frequency is $60$. Find the missing frequencies $x$ and $y$.
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ Frequency $5$ $x$ $20$ $15$ $y$ $5$
| Class | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ |
| Frequency | $5$ | $x$ | $20$ | $15$ | $y$ | $5$ |
Medium
View Solution.......... is not a measure of central tendency.
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View SolutionIn the formula $\bar{x} = A + \frac{\Sigma f_{i} d_{i}}{\Sigma f_{i}}$ for the mean,$d_{i} = \dots$
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View SolutionIn a frequency distribution with total frequency $48$,$\bar{x}=70$,$\Sigma f_{i}=43+f$,and $A=66$. Then,the missing frequency $f=$ .........
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View SolutionThe frequency distribution of marks obtained by $400$ students is given below. If the mean of the frequency distribution is $41.2$,find the missing frequencies $x$ and $y$.
Marks $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ Number of students $26$ $26$ $x$ $110$ $84$ $y$ $36$ $32$
| Marks | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ | $60-70$ | $70-80$ |
| Number of students | $26$ | $26$ | $x$ | $110$ | $84$ | $y$ | $36$ | $32$ |
Medium
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