Coloration of $Br_2/CCl_4$ will be discharged by

$HCl$ does not show the peroxide effect because the reaction mechanism involves the following steps:
$CH_3-CH=CH_2 + \dot{X} \to CH_3-\dot{C}H-CH_2X$ $(I)$
$CH_3-\dot{C}H-CH_2X + HX \to CH_3-CH_2-CH_2X + \dot{X}$ $(II)$
Why does $HCl$ fail to undergo this reaction?

Unbranched alkenes on ozonolysis give $:-$

In the following reaction,$A$ and $B$ respectively are
$A \xrightarrow{HBr} C_2H_5Br \xrightarrow{B} A$

In methyl alcohol solution,bromine reacts with ethylene to yield $BrCH_2CH_2OCH_3$ in addition to $1, 2-dibromoethane$ because:

In the following given reaction,'$A$' is the major product: