HCl does not show the peroxide effect because | vedclass

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(B) The peroxide effect (Kharasch effect) involves a free radical mechanism.For $HCl$,the step involving the abstraction of $H$ from $HCl$ by the alky

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$I$ is exothermic and $II$ is endothermic

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(B) The peroxide effect (Kharasch effect) involves a free radical mechanism.For $HCl$,the step involving the abstraction of $H$ from $HCl$ by the alkyl radical $(CH_3-\dot{C}H-CH_2Cl + HCl 	o CH_3-CH_2-CH_2Cl + \dot{Cl})$ is endothermic because the $H-Cl$ bond is very strong $(431 \ kJ/mol)$.Additionally,the addition of the chlorine radical to the alkene is exothermic,but the overall process is not favorable due to the high energy required to break the $H-Cl$ bond.In contrast,for $HBr$,both steps are exothermic,allowing the reaction to proceed.Therefore,$I$ is exothermic and $II$ is endothermic for $HCl$.

$HCl$ does not show the peroxide effect because the reaction mechanism involves the following steps:
$CH_3-CH=CH_2 + \dot{X} \to CH_3-\dot{C}H-CH_2X$ $(I)$
$CH_3-\dot{C}H-CH_2X + HX \to CH_3-CH_2-CH_2X + \dot{X}$ $(II)$
Why does $HCl$ fail to undergo this reaction?

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$HCl$ does not show the peroxide effect because the reaction mechanism involves the following steps:$CH_3-CH=CH_2 + \dot{X} \to CH_3-\dot{C}H-CH_2X$ $(I)$$CH_3-\dot{C}H-CH_2X + HX \to CH_3-CH_2-CH_2X + \dot{X}$ $(II)$Why does $HCl$ fail to undergo this reaction?