In methyl alcohol solution,bromine reacts with ethylene to yield $BrCH_2CH_2OCH_3$ in addition to $1, 2-dibromoethane$ because:

  • A
    The ion formed initially may react with $Br^{-}$ or $CH_3OH$
  • B
    The methyl alcohol solvates the bromine
  • C
    The reaction follows Markownikoff's rule
  • D
    This is a free-radical mechanism

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