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(B) The dimensional formula of work is given by $[W] = [F] 	imes [s] = [MLT^{-2}][L] = [ML^2 T^{-2}]$.The dimensional formula of angular momentum is

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Work and torque

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(B) The dimensional formula of work is given by $[W] = [F] 	imes [s] = [MLT^{-2}][L] = [ML^2 T^{-2}]$.The dimensional formula of angular momentum is $[L] = [m][v][r] = [M][LT^{-1}][L] = [ML^2 T^{-1}]$.The dimensional formula of torque is $[	au] = [F] 	imes [r] = [MLT^{-2}][L] = [ML^2 T^{-2}]$.The dimensional formula of potential energy is $[U] = [m][g][h] = [M][LT^{-2}][L] = [ML^2 T^{-2}]$.The dimensional formula of linear momentum is $[p] = [m][v] = [M][LT^{-1}] = [MLT^{-1}]$.The dimensional formula of kinetic energy is $[K] = [M][v^2] = [M][LT^{-1}]^2 = [ML^2 T^{-2}]$.The dimensional formula of velocity is $[v] = [LT^{-1}]$.Comparing these,the dimensions of work and torque are both $[ML^2 T^{-2}]$. Therefore,option $B$ is correct.

Choose the physical quantity pair with the same dimensions.

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