If $F_1$ and $F_2$ are the relative strengths of the gravitational and weak nuclear forces respectively,then $\frac{F_2}{F_1}$ is nearly

Match List-$I$ and List-$II$:

List-$I$	List-$II$
$A$. Young's Modulus $(Y)$	$I$. $[M L^{-1} T^{-1}]$
$B$. Co-efficient of Viscosity $(\eta)$	$II$. $[M L^2 T^{-1}]$
$C$. Planck's Constant $(h)$	$III$. $[M L^{-1} T^{-2}]$
$D$. Work Function $(\varphi)$	$IV$. $[M L^2 T^{-2}]$

Choose the correct answer from the options given below:

Some physical constants are given in List-$I$ and their dimensional formulae are given in List-$II$. Match the following:

List-$I$	List-$II$
$(1)$ Planck's constant	$(i)$ $[ML^{-1} T^{-2}]$
$(2)$ Gravitational constant	(ii) $[ML^{-1} T^{-1}]$
$(3)$ Bulk modulus	(iii) $[ML^2 T^{-1}]$
$(4)$ Coefficient of viscosity	(iv) $[M^{-1} L^3 T^{-2}]$

The correct answer is:

Match List-$I$ with List-$II$.

List-$I$	List-$II$
$(a)$ ${R}_{H}$ (Rydberg constant)	$(i)$ ${kg} {m}^{-1} {s}^{-1}$
$(b)$ $h$ (Planck's constant)	$(ii)$ ${kg} {m}^{2} {s}^{-1}$
$(c)$ $u_{B}$ (Magnetic field energy density)	$(iii)$ ${m}^{-1}$
$(d)$ $\eta$ (Coefficient of viscosity)	$(iv)$ ${kg} {m}^{-1} {s}^{-2}$

Choose the most appropriate answer from the options given below:

$A$ steel tape gives correct measurement at $20^{\circ}C$. $A$ piece of wood is being measured with the steel tape at $0^{\circ}C$. The reading is $25 \, cm$ on the tape. The real length of the given piece of wood must be:

Match List $I$ with List $II$:

List $I$	List $II$
$(A)$ Young's Modulus $(Y)$	$(I)$ $[M L^{-1} T^{-1}]$
$(B)$ Co-efficient of Viscosity $(\eta)$	$(II)$ $[M L^2 T^{-1}]$
$(C)$ Planck's Constant $(h)$	$(III)$ $[M L^{-1} T^{-2}]$
$(D)$ Work Function $(\phi)$	$(IV)$ $[M L^2 T^{-2}]$

Choose the correct answer from the options given below: