Cell constant of a conductivity cell is $0.9 \ cm^{-1}$ and resistance shown by $AgNO_3$ solution is $6530 \ \Omega$. What is the conductivity of $AgNO_3$ solution?
- A$725 \ \Omega^{-1} \ cm^{-1}$
- B$5870 \ \Omega^{-1} \ cm^{-1}$
- C$1.38 \times 10^{-4} \ \Omega^{-1} \ cm^{-1}$
- D$4.72 \times 10^{-4} \ \Omega^{-1} \ cm^{-1}$
Explore More
Similar Questions
Which of the following expressions represents the molar conductivity of an electrolyte of type $A_2B_3$?
What is the cell constant,if two platinum electrodes in a conductivity cell are separated by $0.92 \ cm$ and the area of cross-section is $1.2 \ cm^2$ (in $cm^{-1}$)?
$A$ $5.0 \, mmol \, dm^{-3}$ aqueous solution of $KCl$ has a conductance of $0.55 \, mS$ when measured in a cell with a cell constant of $1.3 \, cm^{-1}$. The molar conductivity of this solution is ....... $mS \, m^{2} \, mol^{-1}$. (Round off to the Nearest Integer)
DifficultJEE MAIN 2021
View SolutionThe order of equivalent conductances at infinite dilution for $LiCl$,$NaCl$,and $KCl$ is:
MediumWBJEE 2016
View SolutionThe resistivity of a $0.8 \ M$ solution of an electrolyte is $5 \times 10^{-3} \ \Omega \ cm$. Its molar conductivity is $..... \times 10^4 \ \Omega^{-1} \ cm^2 \ mol^{-1}$. (Nearest integer)
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo