A 5.0 , mmol , dm^{-3} aqueous solution of KC | vedclass

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(C) Given: Concentration $(C) = 5.0 \, mmol \, dm^{-3} = 5.0 	imes 10^{-3} \, mol \, L^{-1} = 5.0 \, mol \, m^{-3}$.Conductance $(G) = 0.55 \, mS = 0

Vedclass · Accepted Answer

$143$

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(C) Given: Concentration $(C) = 5.0 \, mmol \, dm^{-3} = 5.0 	imes 10^{-3} \, mol \, L^{-1} = 5.0 \, mol \, m^{-3}$.Conductance $(G) = 0.55 \, mS = 0.55 	imes 10^{-3} \, S$.Cell constant $(G^*) = 1.3 \, cm^{-1} = 130 \, m^{-1}$.Conductivity $(\kappa) = G 	imes G^* = 0.55 \, mS 	imes 130 \, m^{-1} = 71.5 \, mS \, m^{-1} = 0.0715 \, S \, m^{-1}$.Molar conductivity $(\lambda_m) = \frac{\kappa}{C} = \frac{0.0715 \, S \, m^{-1}}{5.0 \, mol \, m^{-3}} = 0.0143 \, S \, m^2 \, mol^{-1} = 14.3 \, mS \, m^2 \, mol^{-1}$.Rounding to the nearest integer,the value is $14$.

$A$ $5.0 \, mmol \, dm^{-3}$ aqueous solution of $KCl$ has a conductance of $0.55 \, mS$ when measured in a cell with a cell constant of $1.3 \, cm^{-1}$. The molar conductivity of this solution is ....... $mS \, m^{2} \, mol^{-1}$. (Round off to the Nearest Integer)

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