The order of equivalent conductances at infinite dilution for $LiCl$,$NaCl$,and $KCl$ is:

  • A
    $LiCl > NaCl > KCl$
  • B
    $KCl > NaCl > LiCl$
  • C
    $NaCl > KCl > LiCl$
  • D
    $LiCl > KCl > NaCl$

Explore More

Similar Questions

The conductivity of a $0.05 \, M$ solution of a weak monobasic acid is $10^{-3} \, S \, cm^{-1}$. If $\lambda_{m}^{\infty}$ for the weak acid is $500 \, S \, cm^{2} \, mol^{-1}$,calculate the $K_{a}$ of the weak monobasic acid.

If the conductivity of $0.08 \ M$ $KCl$ solution is $2 \times 10^{-2} \ \Omega^{-1} \ cm^{-1}$,what is the molar conductivity of the solution?

Calculate the molar conductivity of $NH_4OH$ at infinite dilution,given that the molar conductivities of $Ba(OH)_2$,$BaCl_2$,and $NH_4Cl$ are $523.28$,$280.0$,and $129.8 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively.

Difficult
View Solution

When is the conductance $G$ equal to the conductivity $k$?

The specific conductance of $0.05 \ M$ $NaOH$ solution is $0.0115 \ S \ cm^{-1}$. What is its molar conductance $(\Lambda_{m})$ in $S \ cm^2 \ mol^{-1}$?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo