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(C) In a $bcc$ (body-centered cubic) unit cell,the total number of particles $(Z)$ is $2$.The packing efficiency of a $bcc$ unit cell is $68\%$,which

Vedclass · Accepted Answer

$2.788 	imes 10^{-23} \ cm^3$

Vedclass · Answer

(C) In a $bcc$ (body-centered cubic) unit cell,the total number of particles $(Z)$ is $2$.The packing efficiency of a $bcc$ unit cell is $68\%$,which means $68\%$ of the total volume of the unit cell is occupied by the particles.Total volume of unit cell = $8.2 	imes 10^{-23} \ cm^3$.Volume occupied by particles = $0.68 	imes 8.2 	imes 10^{-23} \ cm^3 = 5.576 	imes 10^{-23} \ cm^3$.Since there are $2$ particles in the $bcc$ unit cell,the volume occupied by a single particle is $\frac{5.576 	imes 10^{-23}}{2} \ cm^3 = 2.788 	imes 10^{-23} \ cm^3$.

Calculate the volume occupied by a particle in $bcc$ unit cell if the volume of unit cell is $8.2 \times 10^{-23} \ cm^3$.

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