In a metal oxide,O^{2-} ions are arranged in | vedclass

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(B) Let the number of $O^{2-}$ ions in the $hcp$ lattice be $n$.Since the number of octahedral voids $(OHV)$ is equal to the number of lattice points,

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$M_2O_3$

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(B) Let the number of $O^{2-}$ ions in the $hcp$ lattice be $n$.Since the number of octahedral voids $(OHV)$ is equal to the number of lattice points,the number of $OHV = n$.The metal ions occupy $2/3$ of the octahedral voids,so the number of metal ions $= \frac{2}{3}n$.The ratio of metal ions to oxide ions is $M:O = \frac{2}{3}n : n = 2:3$.Therefore,the simplest formula of the oxide is $M_2O_3$.

In a metal oxide,$O^{2-}$ ions are arranged in $hcp$ lattice while metal ions occupy $2/3$ of the octahedral voids. The simplest formula of the oxide is:

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