Calculate the minimum thickness of a soap fil | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For constructive interference in reflected light from a thin film, the condition is given by $2nt = (m + 1/2)\lambda$, where $m = 0, 1, 2, \dots$

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(B) For constructive interference in reflected light from a thin film, the condition is given by $2nt = (m + 1/2)\lambda$, where $m = 0, 1, 2, \dots$ and $n$ is the refractive index of the film.To find the minimum thickness, we set $m = 0$.Thus, $2nt = \lambda/2$.Rearranging for $t$, we get $t = \lambda / (4n)$.Substituting the given values: $\lambda = 532 \,nm$ and $n = 1.33$.$t = 532 / (4 	imes 1.33) = 532 / 5.32 = 100 \,nm$.Therefore, the minimum thickness is $100 \,nm$.

Calculate the minimum thickness of a soap film $(n=1.33)$ that results in constructive interference in reflected light, if the film is illuminated with light whose wavelength in free space is $532 \,nm$. (in $\,nm$)

Similar Questions

In a Fresnel biprism experiment,which of the following light sources is used to identify the central fringe?

Choose the correct statement.

In two separate setups for a Biprism experiment using the same wavelength,fringes of equal width are obtained. If the ratio of slit separation is $2:3$,then the ratio of the distance between the slit and the screen in the two setups is:

$A$ parallel coherent beam of light falls on a Fresnel biprism of refractive index $\mu$ and refracting angle $\alpha$. The fringe width on a screen at a distance $D$ from the biprism will be (wavelength $= \lambda$).

Which of the following phenomena produces the colour in a soap bubble?

Vedclass Test Series

Exam Paper Generator

Online Exam Module