By what percentage will the illumination of t | vedclass

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Question

$P=i^2 R$

$P_{	ext {int }}=I^2{ }_{	ext {int }} R$

$P_{	ext {final }}=\left(0.8 I_{	ext {int }}ight)^2 R$

$\% 	ext { change in power }

Vedclass · Accepted Answer

$36 \%$

Vedclass · Answer

$P=i^2 R$

$P_{	ext {int }}=I^2{ }_{	ext {int }} R$

$P_{	ext {final }}=\left(0.8 I_{	ext {int }}ight)^2 R$

$\% 	ext { change in power }=$

$\frac{P_{	ext {final }}-P_{	ext {int }}}{P_{	ext {int }}} 	imes 100=(0.64-1) 	imes 100=-36 \%$

By what percentage will the illumination of the lamp decrease if the current drops by $20 \%$ ?

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