By using Coulomb’s law, define unit charge.
In $SI$, the unit of charge is Coulomb.
Putting value of $q_{1}=q_{2}=1 \mathrm{C}, r=1 \mathrm{~m}$ in $\mathrm{F}=k \frac{q_{1} q_{2}}{r^{2}}$, then $\mathrm{F}=\frac{1}{4 \pi \epsilon_{0}}=9 \times 10^{9} \mathrm{~N}$
Definition of $1 \mathrm{C}: 1 \mathrm{C}$ is the charge that when placed at a distance of $1 \mathrm{~m}$ from another charge of the same magnitude in vacuum experiences an electrical force of repulsion of magnitude $9 \times 10^{9} \mathrm{~N}$.
Two identical balls having like charges and placed at a certain distance apart repel each other with a certain force. They are brought in contact and then moved apart to a distance equal to half their initial separation. The force of repulsion between them increases $4.5$ times in comparison with the initial value. The ratio of the initial charges of the balls is
Two small spheres each of mass $10 \,mg$ are suspended from a point by threads $0.5 \,m$ long. They are equally charged and repel each other to a distance of $0.20 \,m$. The charge on each of the sphere is $\frac{ a }{21} \times 10^{-8} \, C$. The value of $a$ will be ...... .
$\left[\right.$ Given $\left.g=10 \,ms ^{-2}\right]$
Two identical conducting spheres carry identical charges. If the spheres are set at a certain distance apart, they repel each other with a force $F$. A third conducting sphere identical to the other two, but initially uncharged is touched to one sphere and then to the other before being removed. The force between the original two spheres is now
The electric field between the two spheres of a charged spherical condenser
Two identical tennis balls each having mass $m$ and charge $q$ are suspended from a fixed point by threads of length $l$. What is the equilibrium separation when each thread makes a small angle $\theta$ with the vertical?