By remainder Theorem find the remainder, when | vedclass

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Question

We have $g(x)=x-3$

$\Rightarrow \quad x-3=0$

$\Rightarrow \quad x=3$

Remainder $= p (3)$

$=(3)^{3}-3(3)^{2}+4(3)+50=27-27+12+50$

$=62$

Vedclass · Accepted Answer

$62$

Vedclass · Answer

We have $g(x)=x-3$

$\Rightarrow \quad x-3=0$

$\Rightarrow \quad x=3$

Remainder $= p (3)$

$=(3)^{3}-3(3)^{2}+4(3)+50=27-27+12+50$

$=62$

By remainder Theorem find the remainder, when $p(x)$ is divided by $g(x),$ where

$p(x)=x^{3}-3 x^{2}+4 x+50, g(x)=x-3$