Both the blocks shown in the figure have mass | vedclass

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(B) Let $T$ be the tension in the string and $F$ be the resistive force acting on each block.For block $A$ (moving horizontally to the right):The forc

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$mg / 2$

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(B) Let $T$ be the tension in the string and $F$ be the resistive force acting on each block.For block $A$ (moving horizontally to the right):The forces acting on it are tension $T$ to the right and resistive force $F$ to the left.Since the velocity is constant,the net force is zero:$T - F = 0 \implies T = F$For block $B$ (moving vertically downwards):The forces acting on it are gravity $mg$ downwards,tension $T$ upwards,and resistive force $F$ upwards.Since the velocity is constant,the net force is zero:$mg - T - F = 0 \implies mg = T + F$Substituting $T = F$ into the equation for block $B$:$mg = T + T$$mg = 2T$$T = \frac{mg}{2}$

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