A bomb moving with velocity (40 hat{i} + 50 h | vedclass

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(A) Let the mass of the smaller piece be $m$ and the mass of the larger piece be $4m$. The total mass is $5m$.According to the law of conservation of

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$45 \hat{j} - 35 \hat{k}$

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(A) Let the mass of the smaller piece be $m$ and the mass of the larger piece be $4m$. The total mass is $5m$.According to the law of conservation of linear momentum,the initial momentum equals the final momentum:$P_{initial} = P_{final}$$5m(40 \hat{i} + 50 \hat{j} - 25 \hat{k}) = m(200 \hat{i} + 70 \hat{j} + 15 \hat{k}) + 4m(\vec{v}_{large})$Dividing by $m$:$5(40 \hat{i} + 50 \hat{j} - 25 \hat{k}) = (200 \hat{i} + 70 \hat{j} + 15 \hat{k}) + 4\vec{v}_{large}$$(200 \hat{i} + 250 \hat{j} - 125 \hat{k}) - (200 \hat{i} + 70 \hat{j} + 15 \hat{k}) = 4\vec{v}_{large}$$0 \hat{i} + 180 \hat{j} - 140 \hat{k} = 4\vec{v}_{large}$$\vec{v}_{large} = \frac{180 \hat{j} - 140 \hat{k}}{4} = 45 \hat{j} - 35 \hat{k} 	ext{ m/s}$.

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