Benzaldehyde on reaction with acetophenone in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction between benzaldehyde $(C_6H_5CHO)$ and acetophenone $(CH_3COC_6H_5)$ in the presence of dilute $NaOH$ is a Claisen-Schmidt condensati

Vedclass · Accepted Answer

$C_6H_5CH=CHCOC_6H_5$

Vedclass · Answer

(A) The reaction between benzaldehyde $(C_6H_5CHO)$ and acetophenone $(CH_3COC_6H_5)$ in the presence of dilute $NaOH$ is a Claisen-Schmidt condensation reaction. Benzaldehyde acts as the electrophile,and acetophenone acts as the nucleophile (enolate donor). The reaction proceeds as follows: $C_6H_5CHO + CH_3COC_6H_5 \xrightarrow{NaOH} C_6H_5CH=CHCOC_6H_5 + H_2O$. The final product is benzylidene acetophenone (also known as chalcone).

Column $I$	Column $II$
$A$. $C_6H_5CHO$	$p$. gives precipitate with $2, 4-$dinitrophenylhydrazine
$B$. $CH_3C \equiv CH$	$q$. gives precipitate with $AgNO_3$
$C$. $CN^{-}$	$r$. is a nucleophile
$D$. $I^{-}$	$s$. is involved in cyanohydrin formation

Benzaldehyde on reaction with acetophenone in the presence of sodium hydroxide solution gives

Similar Questions

The given reaction is: $R_2C=O + HCN \rightarrow R_2C(OH)CN$

$Ph-CH_3$ $\xrightarrow{CrO_2Cl_2} (A)$ $\xrightarrow{conc. KOH} Ph-CH_2OH + (B)$
Product $(B)$ of the above reaction is:

Reduction of the lactol $S$ with sodium borohydride $(NaBH_4)$ gives:

Explain aldol condensation and the acidity of the $\alpha$-carbon of aldehydes and ketones. Provide the aldol condensation reactions for $ethanal$ and $propanone$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module