Match the compounds/ions in Column I with the | vedclass

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(D) . $C_6H_5CHO$ (benzaldehyde) is an aldehyde,so it reacts with $2, 4-DNP$ to give a precipitate $(p)$ and acts as an electrophile (not a nucleophil

Vedclass · Accepted Answer

$A-p, q, s$; $B-q$; $C-q, r, s$; $D-q, r$

Vedclass · Answer

(D) . $C_6H_5CHO$ (benzaldehyde) is an aldehyde,so it reacts with $2, 4-DNP$ to give a precipitate $(p)$ and acts as an electrophile (not a nucleophile). It does not form cyanohydrin directly without $CN^-$,but $CN^-$ is the nucleophile involved in that reaction. Wait,let us re-evaluate:$A$. $C_6H_5CHO$: Reacts with $2, 4-DNP$ $(p)$.$B$. $CH_3C \equiv CH$: Terminal alkyne,reacts with ammoniacal $AgNO_3$ to give white precipitate $(q)$.$C$. $CN^-$: Is a nucleophile $(r)$ and is involved in cyanohydrin formation $(s)$. It also reacts with $AgNO_3$ to give $AgCN$ precipitate $(q)$.$D$. $I^-$: Is a nucleophile $(r)$ and reacts with $AgNO_3$ to give $AgI$ precipitate $(q)$.Correct matches:$A: p$$B: q$$C: q, r, s$$D: q, r$Thus,option $D$ is the correct match.

Column $I$	Column $II$
$A$. $C_6H_5CHO$	$p$. gives precipitate with $2, 4-$dinitrophenylhydrazine
$B$. $CH_3C \equiv CH$	$q$. gives precipitate with $AgNO_3$
$C$. $CN^{-}$	$r$. is a nucleophile
$D$. $I^{-}$	$s$. is involved in cyanohydrin formation

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