At a certain place the angle of dip is 30&deg | vedclass

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Question

(c)${B_H} = B\cos \phi ;\;	herefore B = \frac{{{B_H}}}{{\cos \phi }} = \frac{{0.5}}{{\cos {{30}^o}}} = \frac{{0.5}}{{\sqrt 3 /2}} = \frac{1}{{\sqrt 3

Vedclass · Accepted Answer

$\frac{1}{{\sqrt 3 }}$

Vedclass · Answer

(c)${B_H} = B\cos \phi ;\;	herefore B = \frac{{{B_H}}}{{\cos \phi }} = \frac{{0.5}}{{\cos {{30}^o}}} = \frac{{0.5}}{{\sqrt 3 /2}} = \frac{1}{{\sqrt 3 }}$

At a certain place the angle of dip is $30°$ and the horizontal component of earth's magnetic field is $0.50$ Oersted. The earth's total magnetic field is

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