Explain angle of dip.
Explain angle of dip.
If a magnetic needle is perfectly balanced about a horizontal axis so that it can swing in a plane of the magnetic meridian. The needle would make an angle with the horizontal. This is known as the angle of dip (also known as inclination).
Thus, dip is the angle that the total magnetic field $\vec{B}_{\mathrm{E}}$ of the Earth makes with the surface of the Earth.
Figure shows the magnetic meridian plane at a point $\mathrm{P}$ on the surface of the Earth. The plane is a section through the Earth.
The magnetic field of Earth at point $\mathrm{P}$ is $\overrightarrow{\mathrm{B}_{\mathrm{E}}}$.
Similar Questions
At a point $A$ on the earth's surface the angle of $\operatorname{dip}, \delta=+25^{\circ} .$ At a point $B$ on the earth's surface the angle of dip, $\delta=-25^{\circ} .$ We can interpret that
At a point $A$ on the earth's surface the angle of $\operatorname{dip}, \delta=+25^{\circ} .$ At a point $B$ on the earth's surface the angle of dip, $\delta=-25^{\circ} .$ We can interpret that
- [NEET 2019]
The total intensity of earth's magnetic field at the magnetic equator is $5$ $units$. Its value at a magnetic latitude of $37^o $ is equal to
The total intensity of earth's magnetic field at the magnetic equator is $5$ $units$. Its value at a magnetic latitude of $37^o $ is equal to
The earth's magnetic field lines resemble that of a dipole at the centre of the earth. If the magnetic moment of this dipole is close to $8 \times 10^{22}\, Am^2$, the value of earth 's magnetic field near the equator is close to....$Gauss$ (radius of the earth $= 6.4 \times 10^6\, m$)
The earth's magnetic field lines resemble that of a dipole at the centre of the earth. If the magnetic moment of this dipole is close to $8 \times 10^{22}\, Am^2$, the value of earth 's magnetic field near the equator is close to....$Gauss$ (radius of the earth $= 6.4 \times 10^6\, m$)
- [JEE MAIN 2013]
At a certain place, the horizontal component of earth's magnetic field is $\sqrt 3 $times the vertical component. The angle of dip at that place is....$^o$
At a certain place, the horizontal component of earth's magnetic field is $\sqrt 3 $times the vertical component. The angle of dip at that place is....$^o$
A bar magnet of length $14 \,cm$ is placed in the magnetic meridian with its north pole pointing towards the geographic north pole. A neutral point is obtained at a distance of $18\, cm$ from the center of the magnet. If $B _{ H }=0.4 \,G ,$ the magnetic moment of the magnet is $\left(1\, G =10^{-4} T \right)$
A bar magnet of length $14 \,cm$ is placed in the magnetic meridian with its north pole pointing towards the geographic north pole. A neutral point is obtained at a distance of $18\, cm$ from the center of the magnet. If $B _{ H }=0.4 \,G ,$ the magnetic moment of the magnet is $\left(1\, G =10^{-4} T \right)$
- [JEE MAIN 2021]