At a certain place the angle of dip is $30^{\circ}$ and the horizontal component of earth's magnetic field is $0.5 G$. The earth's total magnetic field (in $G$ ), at that certain place, is ................
$\frac{1}{\sqrt{3}}$
$\frac{1}{2}$
$\sqrt{3}$
$1$
Define angle of dip. and Write the definition of declination.
The value of the horizontal component of the earth's magnetic field and angle of dip are $1.8 \times {10^{ - 5}}\,Weber/{m^2}$ and $30°$ respectively at some place. The total intensity of earth's magnetic field at that place will be
The magnetic field of earth is due to
A magnet hung at $45^{\circ}$ with magnetic meridian makes an angle of $60^{\circ}$ with the horizontal. The actual value of the angle of dip is.
A dip needle lies initially in the magnetic meridian when it shows an angle of dip $\theta $ at a place. The dip circle is rotated through an angle $x$ in the horizontal plane and then it shows an angle of dip $\theta '$. Then $\frac{{\tan \theta '}}{{\tan \theta }}$ is