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(D) To determine the number of species that are paramagnetic and have a bond order of $1$,we analyze each species using Molecular Orbital Theory:

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$1$

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(D) To determine the number of species that are paramagnetic and have a bond order of $1$,we analyze each species using Molecular Orbital Theory:						$Species$			$Magnetic \ behaviour$			$Bond \ order$							$H_2$			Diamagnetic			$1$							$He_2^{+}$			Paramagnetic			$0.5$							$O_2^{+}$			Paramagnetic			$2.5$							$N_2^{2-}$			Paramagnetic			$2$							$O_2^{2-}$			Diamagnetic			$1$							$F_2$			Diamagnetic			$1$							$Ne_2^{+}$			Paramagnetic			$0.5$							$B_2$			Paramagnetic			$1$			From the table,only $B_2$ is both paramagnetic and has a bond order of $1$.Therefore,the total number of such species is $1$.

The number of species from the following which are paramagnetic and with bond order equal to $1$ is:
$H_2, He_2^{+}, O_2^{+}, N_2^{2-}, O_2^{2-}, F_2, Ne_2^{+}, B_2$

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The number of species from the following which are paramagnetic and with bond order equal to $1$ is:$H_2, He_2^{+}, O_2^{+}, N_2^{2-}, O_2^{2-}, F_2, Ne_2^{+}, B_2$