What is the correct sequence of bond order fo | vedclass

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Question

(B) The bond order is calculated using the Molecular Orbital Theory $(MOT)$ formula: $B.O. = \frac{1}{2} (N_b - N_a)$.For $O_2^+$ ($15$ electrons): $B

Vedclass · Accepted Answer

$O_2^+ > O_2 > O_2^-$

Vedclass · Answer

(B) The bond order is calculated using the Molecular Orbital Theory $(MOT)$ formula: $B.O. = \frac{1}{2} (N_b - N_a)$.For $O_2^+$ ($15$ electrons): $B.O. = \frac{1}{2} (10 - 5) = 2.5$.For $O_2$ ($16$ electrons): $B.O. = \frac{1}{2} (10 - 6) = 2.0$.For $O_2^-$ ($17$ electrons): $B.O. = \frac{1}{2} (10 - 7) = 1.5$.Thus,the correct sequence is $O_2^+ > O_2 > O_2^-$.

What is the correct sequence of bond order for the given species?

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