Assertion : Potassium ferrocyanide is diamagn | vedclass

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(C) In potassium ferrocyanide,$K_4[Fe(CN)_6]$,$Fe$ is in the $+2$ oxidation state ($Fe^{2+}$: $3d^6$). Since $CN^-$ is a strong field ligand,it causes

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If the Assertion is correct but Reason is incorrect.

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(C) In potassium ferrocyanide,$K_4[Fe(CN)_6]$,$Fe$ is in the $+2$ oxidation state ($Fe^{2+}$: $3d^6$). Since $CN^-$ is a strong field ligand,it causes pairing of electrons,resulting in $t_{2g}^6 e_g^0$ configuration with $n=0$ unpaired electrons,making it diamagnetic.In potassium ferricyanide,$K_3[Fe(CN)_6]$,$Fe$ is in the $+3$ oxidation state ($Fe^{3+}$: $3d^5$). $CN^-$ causes pairing,resulting in $t_{2g}^5 e_g^0$ configuration with $n=1$ unpaired electron,making it paramagnetic.The Assertion is correct.The Reason states that crystal field splitting in ferrocyanide is greater than in ferricyanide. This is incorrect because crystal field splitting energy $(\Delta_o)$ increases with the oxidation state of the metal ion. Since $Fe^{3+}$ has a higher oxidation state than $Fe^{2+}$,the crystal field splitting in the ferricyanide ion is greater than in the ferrocyanide ion. Thus,the Reason is incorrect.

Assertion : Potassium ferrocyanide is diamagnetic,whereas potassium ferricyanide is paramagnetic.
Reason : Crystal field splitting in ferrocyanide ion is greater than that of ferricyanide ion.

Similar Questions

Arrange the following in increasing order of their crystal field splitting energy:
$I. [Co(H_2O)_6]^{3+}$
$II. [Co(NH_3)_6]^{3+}$
$III. [Co(CN)_6]^{3-}$
$IV. [CoF_6]^{3-}$

Which of the following are true about the energy of the given d-orbitals of a tetrahedral complex?
$A$. $d_{xy} = d_{xz} > d_{x^2-y^2}$
$B$. $d_{xy} = d_{yz} > d_{z^2}$
$C$. $d_{x^2-y^2} > d_{z^2} > d_{xz}$
$D$. $d_{x^2-y^2} = d_{z^2}$
Choose the correct answer from the given below:

Draw a figure to show the splitting of $d$ orbitals in an octahedral crystal field.

Which of the following is the correct order of ligand field strength?

The crystal field stabilization energy for a high spin $d^4$ octahedral complex is:

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Assertion : Potassium ferrocyanide is diamagnetic,whereas potassium ferricyanide is paramagnetic.Reason : Crystal field splitting in ferrocyanide ion is greater than that of ferricyanide ion.