Which of the following is the correct order of ligand field strength?

  • A
    $S^{2-} < C_2O_4^{2-} < NH_3 < en < CO$
  • B
    $S^{2-} < C_2O_4^{2-} < NH_3 < en < CO$
  • C
    $NH_3 < en < CO < S^{2-} < C_2O_4^{2-}$
  • D
    $S^{2-} < NH_3 < en < CO < C_2O_4^{2-}$

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Given below are two statements:
Statement $I$: Presence of a large number of unpaired electrons in transition metal atoms results in higher enthalpies of their atomisation.
Statement $II$: $d_{xy} = d_{xz} = d_{yz} < d_{x^2-y^2} = d_{z^2}$ and $d_{x^2-y^2} < d_{xy} = d_{xz} = d_{yz}$ are the $d$-orbital splittings in $[Fe(H_2O)_6]^{3+}$ and $[Ni(Cl)_4]^{2-}$ complex ions respectively.
In the light of the above statements,choose the correct answer from the options given below:

Calculate the crystal field stabilization energy $(CFSE)$ in $[Co(CN)_6]^{3-}$.

The values of the crystal field stabilization energies for a high spin $d^{6}$ metal ion in octahedral and tetrahedral fields,respectively,are :

On the basis of crystal field theory,explain why $Co(III)$ forms a paramagnetic octahedral complex with weak field ligands,whereas it forms a diamagnetic octahedral complex with strong field ligands.

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An ion $M^{2+}$ forms the complexes $[M(H_2O)_6]^{2+}$,$[M(en)_3]^{2+}$,and $[MBr_6]^{4-}$. Match the complex with the appropriate colour.

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