Are the following pair of sets equal ? Give reasons.
$A = \{ 2,3\} ,\quad \,\,\,B = \{ x:x$ is solution of ${x^2} + 5x + 6 = 0\} $
$A = \{ 2,3\} ,\quad \,\,\,B = \{ x:x$ is solution of ${x^2} + 5x + 6 = 0\} $
The equation $x^{2}+5 x+6=0$ can be solved as:
$x(x+3)+2(x+3)=0$
$(x+2)(x+3)=0$
$x=-2$ or $x=-3$
$\therefore A=\{2,3\} ; B=\{-2,-3\}$
$\therefore A \neq B$
Write the solution set of the equation ${x^2} + x - 2 = 0$ in roster form.
$A = \{ x:x \ne x\} $ represents
State which of the following sets are finite or infinite :
$\{ x:x \in N$ and $2x - 1 = 0\} $
Write the following intervals in set-builder form :
$\left[ {6,12} \right]$
Write the following as intervals :
$\{ x:x \in R, - 12\, < \,x\, < \, - 10\} $