Aqueous solution of FeSO_4 does not produce a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $Fe^{2+}$ ions react with $NaOH$ to form a dirty green precipitate of $Fe(OH)_2$.$Fe^{2+} (aq) + 2OH^- (aq) \rightarrow Fe(OH)_2 (s) \downarrow$ (

Vedclass · Accepted Answer

None of these

Vedclass · Answer

(D) $Fe^{2+}$ ions react with $NaOH$ to form a dirty green precipitate of $Fe(OH)_2$.$Fe^{2+} (aq) + 2OH^- (aq) \rightarrow Fe(OH)_2 (s) \downarrow$ (Dirty green ppt.)$Fe^{2+}$ ions react with $NH_3$ solution to form a dirty green precipitate of $Fe(OH)_2$.$Fe^{2+} (aq) + 2NH_3 (aq) + 2H_2O (l) \rightarrow Fe(OH)_2 (s) \downarrow + 2NH_4^+ (aq)$$Fe^{2+}$ ions react with $Na_2CO_3$ to form a precipitate of $FeCO_3$.$Fe^{2+} (aq) + CO_3^{2-} (aq) \rightarrow FeCO_3 (s) \downarrow$Since all the given reagents produce a precipitate with $FeSO_4$,the correct option is $D$.

Aqueous solution of $FeSO_4$ does not produce a precipitate with:

Similar Questions

The only cations present in a slightly acidic solution are $Fe^{3+}$,$Zn^{2+}$,and $Cu^{2+}$. The reagent that when added in excess to this solution would identify and separate $Fe^{3+}$ in one step is

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$(NH_4)_2SO_4 + Sr(OH)_2 \longrightarrow SrSO_4 \downarrow + 2NH_3 \uparrow + 2H_2O$

Nessler's reagent is

Which of the following solutions will yield a black precipitate when $H_2S$ gas is passed through it?

Which of the following pair of cations can be separated by excess $NaOH$ solution?

Vedclass Test Series

Exam Paper Generator

Online Exam Module