The only cations present in a slightly acidic | vedclass

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(C) When $6 \ M \ NaOH$ is added in excess to a solution containing $Fe^{3+}$,$Zn^{2+}$,and $Cu^{2+}$:$1$. $Fe^{3+}$ reacts with $OH^-$ to form a redd

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$6 \ M \ NaOH$

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(C) When $6 \ M \ NaOH$ is added in excess to a solution containing $Fe^{3+}$,$Zn^{2+}$,and $Cu^{2+}$:$1$. $Fe^{3+}$ reacts with $OH^-$ to form a reddish-brown precipitate of $Fe(OH)_3$,which is insoluble in excess $NaOH$.$2$. $Zn^{2+}$ reacts with $OH^-$ to form $Zn(OH)_2$,which dissolves in excess $NaOH$ to form the soluble complex $[Zn(OH)_4]^{2-}$.$3$. $Cu^{2+}$ reacts with $OH^-$ to form a blue precipitate of $Cu(OH)_2$,which is insoluble in excess $NaOH$.However,in the context of standard qualitative analysis,$Fe^{3+}$ is separated as $Fe(OH)_3$ from the others. Given the options,$6 \ M \ NaOH$ is the correct reagent to distinguish $Fe^{3+}$ (as a precipitate) from the amphoteric $Zn^{2+}$ (as a soluble complex).

The only cations present in a slightly acidic solution are $Fe^{3+}$,$Zn^{2+}$,and $Cu^{2+}$. The reagent that when added in excess to this solution would identify and separate $Fe^{3+}$ in one step is

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