Which of the following pair of cations can be | vedclass

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(A) When excess $NaOH$ solution is added to a mixture of $Fe^{3+}$ and $Zn^{2+}$ ions:$1$. $Fe^{3+}$ reacts with $NaOH$ to form a brown precipitate of

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$Fe^{3+}(aq.), Zn^{2+}(aq.)$

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(A) When excess $NaOH$ solution is added to a mixture of $Fe^{3+}$ and $Zn^{2+}$ ions:$1$. $Fe^{3+}$ reacts with $NaOH$ to form a brown precipitate of $Fe(OH)_3$,which is insoluble in excess $NaOH$.$2$. $Zn^{2+}$ reacts with $NaOH$ to form $Zn(OH)_2$,which then dissolves in excess $NaOH$ to form a soluble complex,$[Zn(OH)_4]^{2-}$.$3$. Thus,the mixture can be separated by filtration,where $Fe(OH)_3$ remains as a precipitate and $[Zn(OH)_4]^{2-}$ passes into the filtrate.Therefore,the correct pair is $Fe^{3+}(aq.), Zn^{2+}(aq.)$.

Which of the following pair of cations can be separated by excess $NaOH$ solution?

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