An unbiased die is tossed 500 times. The stan | vedclass

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(C) For a binomial distribution,the standard deviation is given by $\sigma = \sqrt{npq}$.Here,the number of trials $n = 500$.The probability of gettin

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$\frac{25}{3}$

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(C) For a binomial distribution,the standard deviation is given by $\sigma = \sqrt{npq}$.Here,the number of trials $n = 500$.The probability of getting a six in a single toss is $p = \frac{1}{6}$.The probability of not getting a six is $q = 1 - p = 1 - \frac{1}{6} = \frac{5}{6}$.Substituting these values into the formula:$\sigma = \sqrt{500 	imes \frac{1}{6} 	imes \frac{5}{6}}$$\sigma = \sqrt{\frac{2500}{36}}$$\sigma = \frac{50}{6} = \frac{25}{3}$.

An unbiased die is tossed $500$ times. The standard deviation of getting sixes in these $500$ tosses is

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