An unbanked curve has a radius of 60,m. The m | vedclass

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(C) For a car moving on an unbanked circular curve,the centripetal force required for turning is provided by the static friction between the tires and

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$21$

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(C) For a car moving on an unbanked circular curve,the centripetal force required for turning is provided by the static friction between the tires and the road.The condition for the maximum speed $v_{\max}$ is given by the formula:$v_{\max} = \sqrt{\mu rg}$Where:$\mu = 0.75$ (coefficient of static friction)$r = 60\,m$ (radius of the curve)$g = 9.8\,m/s^2$ (acceleration due to gravity)Substituting the values into the formula:$v_{\max} = \sqrt{0.75 	imes 60 	imes 9.8}$$v_{\max} = \sqrt{45 	imes 9.8}$$v_{\max} = \sqrt{441}$$v_{\max} = 21\,m/s$Thus,the maximum speed is $21\,m/s$.

An unbanked curve has a radius of $60\,m$. The maximum speed at which a car can make a turn if the coefficient of static friction is $0.75$,is ...... $m/s$.

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