A molecule M associates in a given solvent ac | vedclass

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Question

(A) For the association reaction $nM \rightleftharpoons (M)_n$,the van't Hoff factor $i$ is related to the degree of association $\alpha$ by the formu

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(A) For the association reaction $nM \rightleftharpoons (M)_n$,the van't Hoff factor $i$ is related to the degree of association $\alpha$ by the formula: $i = 1 - \alpha + \frac{\alpha}{n}$.Given values are $i = 0.9$ and $\alpha = 0.2$.Substituting these values into the equation:$0.9 = 1 - 0.2 + \frac{0.2}{n}$$0.9 = 0.8 + \frac{0.2}{n}$$0.1 = \frac{0.2}{n}$$n = \frac{0.2}{0.1} = 2$.Therefore,the value of $n$ is $2$.

$A$ molecule $M$ associates in a given solvent according to the equation $nM \rightleftharpoons (M)_n$. For a certain concentration of $M$,the van't Hoff factor was found to be $0.9$ and the fraction of associated molecules was $0.2$. The value of $n$ is:

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