An oxide of iron contains 69.9% iron. Its emp | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. Percentage of $Fe = 69.9\%$. Therefore,percentage of $O = 100\% - 69.9\% = 30.1\%$.$2$. Calculate moles of each element:Moles of $Fe = \frac{

Vedclass · Accepted Answer

$Fe_2O_3$

Vedclass · Answer

(B) $1$. Percentage of $Fe = 69.9\%$. Therefore,percentage of $O = 100\% - 69.9\% = 30.1\%$.$2$. Calculate moles of each element:Moles of $Fe = \frac{69.9}{56} = 1.248 	ext{ mol}$.Moles of $O = \frac{30.1}{16} = 1.881 	ext{ mol}$.$3$. Determine the simplest molar ratio:Divide by the smallest value $(1.248)$:$Fe = \frac{1.248}{1.248} = 1$.$O = \frac{1.881}{1.248} \approx 1.5$.$4$. Convert to whole numbers:Multiply by $2$ to get $Fe : O = 2 : 3$.$5$. Thus,the empirical formula is $Fe_2O_3$.

An oxide of iron contains $69.9\%$ iron. Its empirical formula is: (Given: Molar mass of $Fe$ and $O$ are $56$ and $16 \text{ g mol}^{-1}$ respectively.)

Similar Questions

$64 \, g$ of an organic compound contains $24 \, g$ of carbon,$8 \, g$ of hydrogen,and the rest oxygen. The empirical formula of the compound is

The empirical formula of a compound is $CH_{2}O$. $0.0835 \ mol$ of the compound contains $1.0 \ g$ of hydrogen. What is the molecular formula of the compound?

If two compounds have the same empirical formula but different molecular formulas,which of the following do they possess?

$A$ compound contains $8\%$ sulfur by weight. The minimum molecular weight of the compound is:

If two compounds have the same empirical formula but different molecular formulae,they must have:

Vedclass Test Series

Exam Paper Generator

Online Exam Module