The empirical formula of a compound is CH_{2} | vedclass

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(A) The empirical formula is $CH_{2}O$. Let the molecular formula be $(CH_{2}O)_{n}$.This means $1 \ mol$ of the compound contains $2n \ mol$ of hydro

Vedclass · Accepted Answer

$C_{6}H_{12}O_{6}$

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(A) The empirical formula is $CH_{2}O$. Let the molecular formula be $(CH_{2}O)_{n}$.This means $1 \ mol$ of the compound contains $2n \ mol$ of hydrogen atoms.The molar mass of hydrogen is $1 \ g/mol$,so $1 \ mol$ of the compound contains $2n \ g$ of hydrogen.Given that $0.0835 \ mol$ of the compound contains $1.0 \ g$ of hydrogen.Therefore,$1 \ mol$ of the compound contains $\frac{1.0}{0.0835} \approx 11.97 \approx 12 \ g$ of hydrogen.Equating the two: $2n = 12$,which gives $n = 6$.Thus,the molecular formula is $(CH_{2}O)_{6} = C_{6}H_{12}O_{6}$.

The empirical formula of a compound is $CH_{2}O$. $0.0835 \ mol$ of the compound contains $1.0 \ g$ of hydrogen. What is the molecular formula of the compound?

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