An organic compound having the molecular form | vedclass

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(D) The reaction with $I_2$ and dilute $NaOH$ is the iodoform test,which is given by compounds containing the $CH_3CO-$ group or the $CH_3CH(OH)-$ gro

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$1-$phenylethanol

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(D) The reaction with $I_2$ and dilute $NaOH$ is the iodoform test,which is given by compounds containing the $CH_3CO-$ group or the $CH_3CH(OH)-$ group.Among the given options,$1$-phenylethanol $(C_6H_5CH(OH)CH_3)$ contains the $CH_3CH(OH)-$ group.It undergoes oxidation to acetophenone $(C_6H_5COCH_3)$ in the presence of $NaOI$,which then reacts further to produce a yellow precipitate of iodoform $(CHI_3)$.The reaction sequence is:$C_6H_5CH(OH)CH_3$ $\xrightarrow[Oxidation]{NaOI} C_6H_5COCH_3$ $\xrightarrow[Haloform]{I_2+NaOH} C_6H_5COO^- + CHI_3 \downarrow$ (yellow precipitate).

An organic compound having the molecular formula $C_8H_{10}O$ on being heated with $I_2$ and dilute $NaOH$ gives a yellow precipitate. The expected compound is

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