Select the option in which the incorrect majo | vedclass

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(A) Let us analyze each reaction:$A$: The reaction is a Wolff-Kishner reduction. It reduces a carbonyl group to a methylene group. The alkene double b

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(A) Let us analyze each reaction:$A$: The reaction is a Wolff-Kishner reduction. It reduces a carbonyl group to a methylene group. The alkene double bond is unaffected. The product shown is correct.$B$: This is a Hofmann elimination reaction. It involves the thermal decomposition of a quaternary ammonium hydroxide to form an alkene. The product shown is correct.$C$: The reaction of a ketone with $PCl_5$ replaces the carbonyl oxygen with two chlorine atoms (gem-dichloride). The product shown is correct.$D$: The reaction $Ph-I \xrightarrow[\Delta]{Cu} Ph-Ph$ is an Ullmann coupling reaction. However,the Ullmann reaction typically requires an aryl halide (like iodobenzene) and copper powder to form a biaryl compound. The reactant $Ph-I$ is iodobenzene,and the product $Ph-Ph$ is biphenyl. This reaction is actually correct. Wait,re-evaluating the options: In option $A$,the starting material is a ketone with an alkene. Wolff-Kishner reduction $(N_2H_4, OH^-, \Delta)$ reduces the ketone to an alkane. The product shown in the image for $A$ is a ketone,which means the reaction did not occur as expected. Therefore,$A$ is the incorrect product.

Column-$1$ (Reaction)	Column-$2$ (Product)
$A$. Benzaldehyde + $Zn-Hg/HCl$	$I$. Cyclohexanol
$B$. Benzoyl chloride + $H_2/Pd-BaSO_4$	$II$. Benzyl alcohol
$C$. Cyclohexanone + $NH_2NH_2/KOH$	$III$. Toluene
	$IV$. Benzaldehyde
	$V$. Cyclohexane

Select the option in which the incorrect major product is shown.

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