An iron rod of volume $10^{-4} \, m^3$ and relative permeability $1000$ is placed inside a long solenoid wound with $5 \, \text{turns/cm}$. If a current of $0.5 \, A$ is passed through the solenoid, then the magnetic moment of the rod is .... $A m^2$.

The magnetic susceptibility of a material is $7.54 \times 10^{-3}$. The nature and relative permeability of the substance are:

$A$ domain in ferromagnetic iron is in the form of a cube of side length $1\; \mu m$. Estimate the number of iron atoms in the domain and the maximum possible dipole moment and magnetisation of the domain. The molecular mass of iron is $55\; g/mol$ and its density is $7.9\; g/cm^3$. Assume that each iron atom has a dipole moment of $9.27 \times 10^{-24}\; A m^2$.

$A$ bar magnet having length $5 \ cm$ and area of cross-section $4 \ cm^{2}$ has a magnetic moment of $2 \ Am^{2}$. If the magnetic susceptibility is $5 \times 10^{-6}$,the magnetic intensity will be:

$A$ magnetizing field of $5000 \ A/m$ produces a magnetic flux of $4 \times 10^{-5} \ Wb$ in an iron rod of cross-sectional area $0.4 \ cm^2$. The permeability of the rod in $Wb/(A \cdot m)$ is:

The correct relation between total magnetic field $(B)$,magnetic intensity $(H)$,permeability of free space $(\mu_0)$ and susceptibility $(\chi)$ is