A magnetizing field of 5000 A/m produces a m | vedclass

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(C) Given: Magnetizing field,$H = 5000 \ A/m$.Magnetic flux,$\phi = 4 	imes 10^{-5} \ Wb$.Cross-sectional area,$A = 0.4 \ cm^2 = 0.4 	imes 10^{-4} \

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$2 	imes 10^{-4}$

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(C) Given: Magnetizing field,$H = 5000 \ A/m$.Magnetic flux,$\phi = 4 	imes 10^{-5} \ Wb$.Cross-sectional area,$A = 0.4 \ cm^2 = 0.4 	imes 10^{-4} \ m^2 = 4 	imes 10^{-5} \ m^2$.The magnetic flux density $B$ is given by $B = \frac{\phi}{A}$.The permeability $\mu$ is defined as $\mu = \frac{B}{H} = \frac{\phi}{A \cdot H}$.Substituting the values:$\mu = \frac{4 	imes 10^{-5}}{4 	imes 10^{-5} 	imes 5000} = \frac{1}{5000} = 0.0002 = 2 	imes 10^{-4} \ Wb/(A \cdot m)$.

$A$ magnetizing field of $5000 \ A/m$ produces a magnetic flux of $4 \times 10^{-5} \ Wb$ in an iron rod of cross-sectional area $0.4 \ cm^2$. The permeability of the rod in $Wb/(A \cdot m)$ is:

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