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(B) Let the relation $R$ be defined on the set of integers $Z$ such that $(m, n) \in R$ if $m$ is a multiple of $n$,i.e.,$n | m$.$1$. Reflexivity: For

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Reflexive and transitive

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(B) Let the relation $R$ be defined on the set of integers $Z$ such that $(m, n) \in R$ if $m$ is a multiple of $n$,i.e.,$n | m$.$1$. Reflexivity: For any integer $n \in Z$,$n$ is a multiple of $n$ (since $n = n 	imes 1$). Thus,$(n, n) \in R$ for all $n \in Z$. Therefore,$R$ is reflexive.$2$. Symmetry: Consider $m = 6$ and $n = 2$. Here,$6$ is a multiple of $2$,so $(6, 2) \in R$. However,$2$ is not a multiple of $6$. Thus,$(2, 6) 
otin R$. Therefore,$R$ is not symmetric.$3$. Transitivity: Let $(m, n) \in R$ and $(n, p) \in R$. This means $n | m$ and $p | n$. By definition of divisibility,$m = kn$ and $n = lp$ for some integers $k, l$. Substituting $n$,we get $m = k(lp) = (kl)p$. Since $kl$ is an integer,$m$ is a multiple of $p$,so $(m, p) \in R$. Therefore,$R$ is transitive.Conclusion: The relation is reflexive and transitive.

An integer $m$ is said to be related to another integer $n$ if $m$ is a multiple of $n$. Then the relation is

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