An inductor of inductance $L = 400 \ mH$ and resistors of resistance $R_1 = 2 \ \Omega$ and $R_2 = 2 \ \Omega$ are connected to a battery of emf $E = 12 \ V$ as shown in the figure. The internal resistance of the battery is negligible. The switch $S$ is closed at $t = 0$. The potential drop across $L$ as a function of time is:

  • A
    $6e^{-5t} \ V$
  • B
    $\frac{12}{t}e^{-3t} \ V$
  • C
    $6(1 - e^{-t/0.2}) \ V$
  • D
    $12e^{-5t} \ V$

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