(C) The efficiency $\eta$ of a Carnot engine is given by the formula: $\eta = 1 - \frac{T_2}{T_1}$.Here,$T_1$ is the higher temperature and $T_2$ is t

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(C) The efficiency $\eta$ of a Carnot engine is given by the formula: $\eta = 1 - \frac{T_2}{T_1}$.Here,$T_1$ is the higher temperature and $T_2$ is the lower temperature in Kelvin.$T_1 = 227 + 273 = 500\,K$.$T_2 = 127 + 273 = 400\,K$.Efficiency $\eta = 1 - \frac{400}{500} = 1 - 0.8 = 0.2$.Since efficiency $\eta = \frac{W}{Q_1}$,where $W$ is the work done and $Q_1$ is the heat absorbed at the higher temperature:$W = \eta \times Q_1 = 0.2 \times 6\,kcal = 1.2\,kcal$.

Class 11 Physics Thermodynamics Heat Engine and Carnot Cycle

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An ideal gas heat engine operates in a Carnot cycle between $227^{\circ}C$ and $127^{\circ}C$. It absorbs $6\,kcal$ at the higher temperature. The amount of heat (in $kcal$) converted into work is equal to

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An ideal gas heat engine operates in a Carnot cycle between $227^{\circ}C$ and $127^{\circ}C$. It absorbs $6\,kcal$ at the higher temperature. The amount of heat (in $kcal$) converted into work is equal to

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