A car engine has a power of 20 kW. The car ma | vedclass

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(A) The power of the car engine is $P = 20 kW = 20,000 W$.The time taken for the round trip is $t = 1 hour = 3600 s$.The useful work done by the engin

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$180000$

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(A) The power of the car engine is $P = 20 kW = 20,000 W$.The time taken for the round trip is $t = 1 hour = 3600 s$.The useful work done by the engine is $W = P 	imes t = 20,000 	imes 3600 = 7.2 	imes 10^7 J$.The thermal efficiency of the engine is given by $\eta = \frac{W}{Q_{in}}$, where $Q_{in}$ is the energy generated by fuel combustion.Given $\eta = 40 \% = 0.4$, we have $Q_{in} = \frac{W}{\eta}$.$Q_{in} = \frac{7.2 	imes 10^7 J}{0.4} = 18 	imes 10^7 J$.Converting to $kJ$, $Q_{in} = 180,000 kJ$.

$A$ car engine has a power of $20 kW$. The car makes a round trip of $1$ hour. If the thermal efficiency of the engine is $40 \%$ and the ambient temperature is $300 K$, the energy generated by fuel combustion is: (in $kJ$)

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