An ideal gas follows the path shown in the fi | vedclass

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(B) The net work done in a cyclic process is equal to the area enclosed by the $p-V$ diagram.For the given triangle $ABC$,the base is $(3 V_{1} - V_{1

Vedclass · Accepted Answer

$-3 p_{1} V_{1}$

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(B) The net work done in a cyclic process is equal to the area enclosed by the $p-V$ diagram.For the given triangle $ABC$,the base is $(3 V_{1} - V_{1}) = 2 V_{1}$ and the height is $(4 p_{1} - p_{1}) = 3 p_{1}$.The magnitude of the area is $	ext{Area} = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes (2 V_{1}) 	imes (3 p_{1}) = 3 p_{1} V_{1}$.Since the cycle $A ightarrow B ightarrow C ightarrow A$ is traversed in an anticlockwise direction,the work done by the gas is negative.Therefore,the net work done is $W_{	ext{cycle}} = -3 p_{1} V_{1}$.

An ideal gas follows the path shown in the figure. The net work done in the whole cycle is

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