In a cyclic process,a gas is taken from state | vedclass

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(A) In a $P-V$ diagram,the area under the curve represents the work done by the gas. For the path $A \rightarrow B$ via path $-I$,the gas expands (vol

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positive work is done on the gas

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(A) In a $P-V$ diagram,the area under the curve represents the work done by the gas. For the path $A \rightarrow B$ via path $-I$,the gas expands (volume increases),so the work done by the gas is positive $(W_I > 0)$. For the path $B \rightarrow A$ via path $-II$,the gas is compressed (volume decreases),so the work done by the gas is negative $(W_{II} Since the area under path $-II$ is larger than the area under path $-I$ (as seen in the diagram),the magnitude of work done during compression is greater than the work done during expansion. Therefore,the net work done in the cycle $(W_{net} = W_I + W_{II})$ is negative. Negative net work done by the gas means that positive work is done on the gas.

In a cyclic process,a gas is taken from state $A$ to $B$ via path $-I$ as shown in the indicator diagram and taken back to state $A$ from state $B$ via path $-II$. In the complete cycle

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