An ellipsoidal cavity is carved within a perfect conductor. A positive charge $q$ is placed at the centre of the cavity. The points $A$ and $B$ are on the cavity surface as shown in the figure. Then
Electric field near $A$ in the cavity = Electric field near $B$ in the cavity
Total electric field flux through the surface of the cavity is $q/{\varepsilon _0}$
Potential at $A = $ Potential at $B$
Both $(b)$ and $(c)$
Given below are two statement: one is labelled as Assertion $A$ and the other is labelled as Reason $R$.
Assertion $A:$ If an electric dipole of dipole moment $30 \times 10^{-5}\,Cm$ is enclosed by a closed surface, the net flux coming out of the surface will be zero.
Reason $R$ : Electric dipole consists of two equal and opposite charges.
In the light of above, statements, choose the correct answer from the options given below:
A cylinder of radius $R$ and length $L$ is placed in a uniform electric field $E$ parallel to the cylinder axis. The total flux for the surface of the cylinder is given by-
What is the net flux of the uniform electric field of $E =3 \times 10^{3} i\; N / C $ through a cube of side $20\; cm$ oriented so that its faces are parallel to the coordinate planes?
An infinite line charge is at the axis of a cylinder of length $1 \,m$ and radius $7 \,cm$. If electric field at any point on the curved surface of cylinder is $250 \,NC ^{-1}$, then net electric flux through the cylinder is ............ $Nm ^2 C ^{-1}$
A hollow cylinder has a charge $q$ coulomb within it. If $\phi$ is the electric flux in units of $volt-meter$ associated with the curved surface $B,$ the flux linked with the plane surface $A$ in units of $V-m$ will be