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(B) The magnetic field $\overrightarrow{B}$ inside a long current-carrying solenoid is uniform and directed along its axis.When an electron moves with

Vedclass · Accepted Answer

$B$ and $C$ only

Vedclass · Answer

(B) The magnetic field $\overrightarrow{B}$ inside a long current-carrying solenoid is uniform and directed along its axis.When an electron moves with velocity $\overrightarrow{v}$ along the axis of the solenoid,the velocity vector $\overrightarrow{v}$ is parallel to the magnetic field vector $\overrightarrow{B}$.The magnetic force $\overrightarrow{F}$ on a moving charge is given by the Lorentz force formula: $\overrightarrow{F} = q(\overrightarrow{v} 	imes \overrightarrow{B})$.Since $\overrightarrow{v}$ and $\overrightarrow{B}$ are parallel,the angle $	heta$ between them is $0^{\circ}$.Therefore,the magnitude of the magnetic force is $F = qvB \sin(0^{\circ}) = 0$.Since the net magnetic force is zero,the electron will not experience any force and will continue to move along the axis with constant velocity.Thus,statements $B$ and $C$ are correct.

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